hi all. here is the question:

there were 17 dogs who found a pile of bones. they decided to divide the bones equally but after they divided the bones, there was 5 extra bones left.

One dog left so there was 16 dogs left. They decided to divide up the bones again, but this time had 10 extra bones left.

Another dog left so there were 15 dogs left, when they divided up the bones again, there was 0 extra bones left.

Two questions:

1. what is the minimum number of bones in the pile?

2. what is another possible solution to the number of bones in the pile?

Answer:

using brute force of multiples of 15, I found that 90 bones work and it is the smallest number possible. (if you disagree please let me know!)

what is another number of bones that can work? Also, can someone tell me how to set this question up? I am very confused. Thanks!!!!