why are you adding? you should be multiplying...a) How many have f(3)=8? How many have f(3) 8?
There is one object being distributed to one recipient for f(3)=8, plus 6 objects being distributed to 9 recipients. So there are possible functions that have f(3)=8. For the second part of the question, has 8 different functions plus 6 objects being distributed to 9 recipients. So there are possible functions that have .
I am not familiar with the notation you are using. ?b) How many have and are one-to-one?
In this case we have 8 possible functions for plus .
Anyway, I would disagree. We have 8 choices for what to map 3 to. Having made that choice, we again have 8 choices to map the second element to, then 7, then 6, then 5, etc. The total number of functions with this criteria, therefore, is
i agreec) How many have even for all i?
There are 4 even numbers in the Codomain, which gives distributions of 7 objects to 4 recipients.
I agreed) How many have ?
That would be 7 objects distributed to 2 recipients, so .
what is your definition of here? Because, unless we restrict the domain somehow, the inverse will technically never be defined.e) How many in which is not a function?
This would be the same as the total number of distributions of 7 objects to 9 recipients minus the number which have a one-to-one relationship which would be .So the answer is .