One more for tonight.

Expand (2c-3d)^5 Using the Binomial Theorem

I am pretty weak on this whole binomial theorem thing. It seems like it should be fairly simple and straightforward but I keep getting hung up. Here is where I am at so far

and it isnt much

a=2c, b=-3d, n=5

(2c-3d)^5 = (a+b)^5

That is about it. Not sure if I am even on the right track. thanks for the help.

pwr