Hello Is this correct? [(AUBUC)∩(AUB)]-[(AU(B-C))∩A] = CUB Thanks
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The Venn diagrams do not seem to bear that conclusion out. I think you can see that $\displaystyle (A\cup B\cup C)\cap(A\cup B)=A\cup B$. Can you similarly simplify $\displaystyle A\cup(B-C))\cap A$?
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