Think I got it, that's just the answer from the equation.. x = 101. So 127 X 101 = 1 (mod 583)
Hey guys, I need help with this question. "Use Euclids algorithm to find integer solutions of the given equation and hence find solutions of the congruence equations that are also given."
Equation: 127a + 583b = 1
Congruence equation: 127x = 1 (mod 583)
After doing Euclids algorithm, I found a = 101 and b = -22. But knowing this information, how do I find x in: 127x = 1 (mod 583)