How many functions f: [6] --> [4] have f(3)=2? Just to make sure I'm understanding how to do this correctly: This would be the same as how many functions f: [5] --> [4] ? The answer would be , correct?
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Originally Posted by oldguynewstudent How many functions f: [6] --> [4] have f(3)=2? This would be the same as how many functions f: [5] --> [4] ? The answer would be , correct? Yes that is correct.
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