Thread: How many functions f: [6] --> [4] have f(3)=2?

How many functions f: [6] --> [4] have f(3)=2?

Just to make sure I'm understanding how to do this correctly:

This would be the same as how many functions f: [5] --> [4] ?

The answer would be , correct?

Originally Posted by oldguynewstudent

How many functions f: [6] --> [4] have f(3)=2?
This would be the same as how many functions f: [5] --> [4] ?
The answer would be , correct?

Yes that is correct.