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Math Help - How many functions f: [6] --> [4] have f(3)=2?

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    Member oldguynewstudent's Avatar
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    How many functions f: [6] --> [4] have f(3)=2?

    How many functions f: [6] --> [4] have f(3)=2?

    Just to make sure I'm understanding how to do this correctly:

    This would be the same as how many functions f: [5] --> [4] ?

    The answer would be 4^5 , correct?
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    Quote Originally Posted by oldguynewstudent View Post
    How many functions f: [6] --> [4] have f(3)=2?
    This would be the same as how many functions f: [5] --> [4] ?
    The answer would be 4^5 , correct?
    Yes that is correct.
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