How many functions f: [6] --> [4] have f(3)=2?
Just to make sure I'm understanding how to do this correctly:
This would be the same as how many functions f: [5] --> [4] ?
The answer would be $\displaystyle 4^5$ , correct?
How many functions f: [6] --> [4] have f(3)=2?
Just to make sure I'm understanding how to do this correctly:
This would be the same as how many functions f: [5] --> [4] ?
The answer would be $\displaystyle 4^5$ , correct?