How many functions f: [6] --> [4] have f(3)=2?

Just to make sure I'm understanding how to do this correctly:

This would be the same as how many functions f: [5] --> [4] ?

The answer would be $\displaystyle 4^5$ , correct?

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- Jun 6th 2010, 11:36 AMoldguynewstudentHow many functions f: [6] --> [4] have f(3)=2?
How many functions f: [6] --> [4] have f(3)=2?

Just to make sure I'm understanding how to do this correctly:

This would be the same as how many functions f: [5] --> [4] ?

The answer would be $\displaystyle 4^5$ , correct? - Jun 6th 2010, 11:48 AMPlato