How many functions f: [6] --> [4] have f(3)=2?

• June 6th 2010, 12:36 PM
oldguynewstudent
How many functions f: [6] --> [4] have f(3)=2?
How many functions f: [6] --> [4] have f(3)=2?

Just to make sure I'm understanding how to do this correctly:

This would be the same as how many functions f: [5] --> [4] ?

The answer would be $4^5$ , correct?
• June 6th 2010, 12:48 PM
Plato
Quote:

Originally Posted by oldguynewstudent
How many functions f: [6] --> [4] have f(3)=2?
This would be the same as how many functions f: [5] --> [4] ?
The answer would be $4^5$ , correct?

Yes that is correct.