nCr = 10C3 = 10!/3!(10 - 3)! = 120
How would I do...
A new computer graphics company employs 10 programmers. The company decides to expand into digital animation and needs to transfer 3 of the programmers into the new department. How many different combinations of 3 programmers can be chosen to transfer to the new department?
I thought I should just do 3x10=30 but the answer is 120.