That looks right to me.
Hey guys, can someone please check my solution if its correct for the following question thankyou!!!
QUESTION:
Use inclusion-exclusion to find the number of solutions in non-negative integers to:
with the conditions , , .
MY SOLUTION
STEP 1: Solutions for greater than conditions.
Condition 1:
Condition 2:
Let
Therefore:
So
STEP 2: Solutions for less than conditions.
Condition 1:
Condition 2:
Condition 1:
Let
Therefore:
So
Condition 2:
Let
Therefore:
So
Now we need to find solutions for
Therefore:
NO SOLUTIONS SINCE RHS IS A NEGATIVE INTEGER.......
therefore final solutions: