# Math Help - Counting passwords

How many eight-character passwords are there if each character is either an uppercase letter A-Z, a lowercase letter a-z, or a digit 0-9, and where at least one character and at least one number are used?

Total number of passwords possible = $62^8$

then $10^8$ of these are all numbers and $52^8$ are all letters.

So the answer would be $62^8$ - $10^8$ - $52^8$.

Correct?

2. Congratulations my friend, you have really come a long way.
Yes indeed that is correct.
Keep up that good work.