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Math Help - Counting

  1. #1
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    Counting

    In how many ways can 6 different candies be passed out to nine people if everyone can receive just one?

    can we just assume that they have a choice of 6 each time? Like:
    6*6*6*6*6*6*6*6*6

    The next problem asks the same question but in this case everyone can have any number of candies....if the first part isn't right then this part won't be right.


    Any clarification?
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  2. #2
    Junior Member slovakiamaths's Avatar
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    Quote Originally Posted by chubbs145 View Post
    In how many ways can 6 different candies be passed out to nine people if everyone can receive just one?

    can we just assume that they have a choice of 6 each time? Like:
    6*6*6*6*6*6*6*6*6

    The next problem asks the same question but in this case everyone can have any number of candies....if the first part isn't right then this part won't be right.


    Any clarification?
    ^9c_6=\frac{9*8*7}{3*2*1}=84
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  3. #3
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    Quote Originally Posted by chubbs145 View Post
    In how many ways can 6 different candies be passed out to nine people if everyone can receive just one?
    This is a simple permutation: ^9\mathcal{P}_6=\frac{9!}{(9-6)!}=9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4~.
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  4. #4
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    Hello, chubbs145!

    In how many ways can 6 different candies be passed out to nine people
    if everyone can receive just one?

    Plato is absolutely correct!



    The next problem asks the same question
    but in this case, everyone can have any number of candies.

    For each of the 6 candies, there are 9 choices of people to give it to.

    Answer: . 9^6 \:=\:531,\!441 ways.

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