The sum (from n=1 to infinity) of ng(n), where g(n)=(1/3)^(n-1) Thanks.
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Originally Posted by feyomi The sum (from n=1 to infinity) of ng(n), where g(n)=(1/3)^(n-1) Thanks. Since,
Last edited by Anonymous1; May 6th 2010 at 12:49 PM.
Originally Posted by feyomi The sum (from n=1 to infinity) of ng(n), where g(n)=(1/3)^(n-1) Thanks. Hi feyomi, For the geometric series, the first term is 1 and the common ratio is 1/3, hence it's sum to infinity is
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