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Math Help - One more permutation problem

  1. #1
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    One more permutation problem

    Sorry for bothering you guys again but here's another problem that I'm having difficulty with:

    How many numbers can be formed using all of the digits 1, 2, 3, 4, 5, 6, and 7 if the odd digits must be in ascending order and the even digits in descending order?

    Thanks for your time!
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  2. #2
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    There are seven places, select four to place the odd digits.
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