Just needed somebody to verify this

In the pick-6 lottery involving the numbers 1-40, you win the Match-4 prize if exactly four of your six numbers appear on the winning ticket. In a given lottery drawing, how many different tickets would win the Match-4 prize?

$\displaystyle \left(\left({6\atop 4}\right)\right)$ = $\displaystyle \left({6+4-1\atop 4}\right)$ = 126

Thanks