What about A=B=1, C=1, D=-1?
I got down to this
I then divived both sides by "A"
My proof goes as following....
It is possible that B=A.....eg A=6....B=6.....A^2=B^2.......36=36
So if this is possible. this equation breaks down to
C=D.... However it is clear that C is not always equal to D
Can anyone recommend a better proof?
i ended up with
Which is not always TRUE.... all i have to do is show one case where it is not true.....
Defunkt. For A=B=1,C=-1,D=1
1=1/-1....which is false. Do you think this proof is ok?
All im proving is that it doesnt work for all numbers of A and B... shouldnt all
i have to show is one FALSE? thanks for the input