# Factoring numbers into product of primes

• Apr 13th 2010, 04:44 AM
jvignacio
Factoring numbers into product of primes
Hey guys, need to confirm my answers for these following question.

Factoring the following numbers into the product of primes:

a) $27$

= $27 \cdot 1$

b) $1024$

= $2^{10}$

c) $625000$

= $2^3 \cdot 5^7$

d) $12!$ (Also equals 479001600)

= $2^{10} \cdot 3^5 \cdot 5^2 \cdot 7 \cdot 11$

Are my answers correct according to what the question is asking? thanks
• Apr 13th 2010, 05:48 AM
Quote:

Originally Posted by jvignacio
Hey guys, need to confirm my answers for these following question.

Factoring the following numbers into the product of primes:

a) $27$

= $27 \cdot 1$

b) $1024$

= $2^{10}$

c) $625000$

= $2^3 \cdot 5^7$

d) $12!$ (Also equals 479001600)

= $2^{10} \cdot 3^5 \cdot 5^2 \cdot 7 \cdot 11$

Are my answers correct according to what the question is asking? thanks

Sooooo close!

You got the harder ones right and the easy one wrong.

$27 = 3^3$
• Apr 13th 2010, 06:17 AM
jvignacio
Quote:

$27 = 3^3$