So b) is ONTO.
p.S
I need help trying to understand the question and knowing what to look for.... I don't really need help solving it. Hints don't help much either.
Can someone please explain how to approach such a problem and what I need to look for in order to prove something is onto or one-to-one?
So I know the answer b/c I went over it with my prof. but I still dont really understand it, can someone please explain?
Here it is:
F:N -> {0,1}
F(n)= {0 if 3 does not |n, 1 if 3|n)
a) is NOT one-to-one <- I know this is due to having more then one value mapped to the same second value, but I dont understand how this conclusion is figured out given the information of the problem.
Proof:
Consider n(base1)= 1 and n(base2)= 2
Then F(n(base1)=F(n(base2))=0 but n(base1)DOES NOT EQUAL 2.
Also,
Is F onto? YES
Proof:
Let y E {0,1}
if y=0,choose n=1 then, n E N and F(n)=y since F(1)=0
If y=1, choose n-3 then, n E N and F(n)=y since F(3)=1.
Can someone please explain how this proof was reached and the logic behind whats going on in detail so i understand it once and for all?
Thank You in advance,
Matt H