Define by the rule
h(n) = 4n-1 for all
Is h onto?
I know that h is not onto because if we suppose then we have to search an such that h(n) = m, and for there doesn't exist any integer n.
It is all right.As A Counter Example
h(n) = 0
4n-1 = 0
4n = 1
n = 1/4 Z
Role of Rule in Proving a Function? Help!
But, what is the purpose of the rule h(n) = 4n-1 ? because if we stuck on this rule then 4n-1 will never be equal to 0.
Any help??According to h(n) = 4n-1 For All
n = -1 Then 4(-1) - 1
n = 0 Then 4(0) - 1
n = 1 Then 4(1) - 1
n = 2 Then 4(2) - 1
...So on, and in this case 4n-1 will always be an integer thus h will become onto.