Hello, differentiate!

I will assume it is a *circular* table.

can sit anywhere; it doesn't matter.

Then 's seat is already determined.

So far, we have these 8 chairs with two of them occupied. Code:

A
/ \
X X
| |
X X
| |
X X
\ /
B

Remove two of the chairs.

Place stools between the remaining six chairs. Code:

A
o o
X X
o o
X X
o o
B

Seat in any of the 6 empty stools.

Seat is any of the 5 remaining stools.

. . There are: . ways.

Then seat in the four chairs.

. . There are: . ways.

Therefore, there are: . ways.