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**Possible actuary** I am not understanding what this question is asking.

Question: Find another formula suggested by Exercises 3 and 4, and verify your formula by mathematical induction.

Exercise 3: Prove that 1+3+5+...+(2n-1)=n^2 for every positive integer n by one, by mathematical induction and two, by adding 1+3+5+...+(2n-1) and (2n-1)+(2n-3)+...+1.

Exercise 4: Use mathematical induction to prove that 1+5+9+...+(4n-3)=2n^2-n for every positive integer n.

The only idea I have is they want me to change (2n-1) and (4n-3) to fit the series of course.