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Math Help - Prove a/b and a/c then a/ (3b-7c)

  1. #1
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    Prove a/b and a/c then a/ (3b-7c)

    I have to prove that a/b and a/c then a/ (3b-7c), where a, b, and c are integers. I know this is true but I need help with the proof.

    Do I assume a does not /(3b-7c)?

    I am so lost....please help
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  2. #2
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    I assume that a/b means "a divides b". A vertical bar usually denotes "divides".

    If a divides b, then b = k * a for some integer k, and similarly for c. Now, both b and c are expressed through a, so 3b - 7c can also be expressed through a.
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  3. #3
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    Smile

    Thanks!
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