Let A be anyfamily sets. Prove $\displaystyle \bigcap_{A \epsilon A} A \subset \bigcup_{A \epsilon A} A $.NONEMPTY

Printable View

- Mar 22nd 2010, 09:52 AMonemorenonempty family sets
Let A be any

family sets. Prove $\displaystyle \bigcap_{A \epsilon A} A \subset \bigcup_{A \epsilon A} A $.__NONEMPTY__ - Mar 22nd 2010, 11:55 AMPlato
Please review this posting. Some of the notation seems a bit off.

Like $\displaystyle A\in A$.