I need help with finding how many 8-digit numbers there are containing no more than three zeros?
For exampel numbers like 10001111.
Thanx in advance.
(Hint: you have 8 places, and you are choosing none to be a zero, then one to be a zero, then two to be a zero, then three to be a zero...)
Finally, subtract these from the total number of numbers to get your result!