A coin is flipped 10 times. How many outcomes have at most 3 heads? My best guess is [C(10,3)]+[C(10,2)]+[C(10,1)] = 120 + 45 + 10 = 175 outcomes. Is this the solution?
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Originally Posted by sedemihcra A coin is flipped 10 times. How many outcomes have at most 3 heads? My best guess is [C(10,3)]+[C(10,2)]+[C(10,1)] = 120 + 45 + 10 = 175 outcomes. Is this the solution? What about the possibility of all 10 being tails?
Never thought of having all of them being tails. I guess the solution would then be: [C(10,3)]+[C(10,2)]+[C(10,1)] + [C(10,0)] = 120 + 45 + 10 + 1 = 176 outcomes.
Yes. If the question had been worded... For outcomes involving "at least 1 head", how many outcomes contain at most 3 heads... your first answer was fine.
Thanks a bunch.
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