Originally Posted by
mathh18 i'm trying to prove that recursive formula 2[a(sub)k-1] -3 and closed formula [a(sub)n]= 2^(n-1) +3 are equal.
i have [a(sub)m] = 2[a(sub)m-1]-3 =
2(2^(m-3)+3) -3 =
2^(m-2) +3
that is close, but slightly off than what i'm trying to prove..what should i do to make it 2^(m-1) +3 ?
sorry for the typing, it's confusing on the computer