Induction for an inequality

hmmm... this is an interesting question, but I'm not sure if I've understood it correctly. Do you mean:
$<br /> a_{n + 1} = (\frac{3 + a_n^2}{2a_n})$ ; $n > 1, a_n > \sqrt{3}<br />$ ?

Oops, took me a while to figure out what was meant by the question...

$<br /> a_{n + 1} = \frac{3 + (\sqrt{3})^2}{2(\sqrt{3})} = \frac{3}{\sqrt{3}} =\sqrt{3}$ ; substitue $a_n = \sqrt{3}$

mind you that's not an answer!