Thread: Basic Question about Operations on Sets

I'm just starting out in group theory, and I'm having a bit of trouble with this question.

Let S={a,b,c}.

1) How many elements does the set SxS contain?

I think the answer to this is 9, {a,a}{a,b}{a,c}{b,a}{b,b}{b,c}{c,a}{c,b}{c,c}. My only possible worry is that {a,b}={b,a}, but I'm basing my understanding of this as kind of like a graph, where the point {1,2} is not equal to {2,1}.

2) How many operations are there on S?

I don't really know how to go about this part. My understanding of an operation is that it takes two elements in the set and maps them to one element in the set. So maybe if I say that every element in SxS can be mapped to one of three elements, then there are 9 times 3 operations i.e. 27. Again though, I'm not totally clear on it.

3) Find the Caley table for an operation such that is a group with identity element a.

I think if I set up the table so that , this is a group. It has an identity, each element has an inverse, and I'm pretty sure it's associative.

4) Prove that the operation you have found is the only operation on S such that is a group with identity element a.

Well, a is the identity. a is also it's own inverse, while b and c are inverses of each other, so every element is invertible. Which leaves associativity. Is the only way to show this by computign every combination of elements? Also, I'm not sure how to show it it the "only" operation.

5) Finally, write down the Cayley table of each operation on S such that is a group, and determine which of these operations is commutative.

I know that I could just cycle the elements in the set and get analogues of the previous question with b and c as identity elements, instead of a. But I can't tell if there are any other operations that form a group. I know that when I get that part, if the Cayley table is symmetric, it is a commutative operation.

I'm just starting out on this topic, so any help/pointers would be much appreciated.
Thanks in advance.

Originally Posted by jameson2

I'm just starting out in group theory, and I'm having a bit of trouble with this question.

Let S={a,b,c}.

1) How many elements does the set SxS contain?

It can be shown fairly easy by a combinatorial argument that

2) How many operations are there on S?

What does operation mean? How many mappings are there? I think once again it would be easier to show combinatorially that

3) Find the Caley table for an operation such that is a group with identity element a.

I know this is a little above what you are doing right now, but this will look EXACTLY like . But, for now draw up the Cayley and fill in the squares remembering that etc.

You can do the rest.

Originally Posted by jameson2

Let S={a,b,c}.
2) How many operations are there on S?
I don't really know how to go about this part. My understanding of an operation is that it takes two elements in the set and maps them to one element in the set. So maybe if I say that every element in SxS can be mapped to one of three elements, then there are 9 times 3 operations i.e. 27. Again though, I'm not totally clear on it.

Because you said that this is beginning group theory, I will assume the standard definition of operation:
a mapping
As such the number of operations on is .
In this case it is simply . The number of functions fron a set of nine to a set of three.