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Math Help - Conjunction Disjunction confuse.

  1. #1
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    Conjunction Disjunction confuse.

    Given the pair of statements

    p : If 3 >2, then 3 x 0 > 2 x 0

    q: If 4=5, then 5=9
    Write their conjunction and disjunction, indicating the truth value of each compound statement formed.


    The problem above confuse me. I know this type of problem though.

    p: One is an even integer. q: Nine is a positive integer.
    A. (a) One is an even integer and nine is a positive integer.
    (b) One is an even integer or nine is a positive integer. (T)
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  2. #2
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    Do the new problem exactly as you have done in the sample you gave.
    Just realize that q is false and p is true.
    Last edited by Plato; February 1st 2010 at 11:03 AM.
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  3. #3
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    Is this how the answer should be? It confuse me because these number don't look right .
    a) Conjunction
    If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
    a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0
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  4. #4
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    Quote Originally Posted by iMoons View Post
    Is this how the answer should be? It confuse me because these number don't look right .
    a) Conjunction
    If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
    a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0
    I cannnot say if they are correct or not.
    You understand that I did not give the assignment so I don't know what is expected.
    However, the first is a conjunction of the two. It is false.
    The second is a disjunction. It is true.
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  5. #5
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    Ok. Thank you. It clear to me now.
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  6. #6
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    Quote Originally Posted by iMoons View Post
    Is this how the answer should be? It confuse me because these number don't look right .
    a) Conjunction If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
    a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0

    Try these:
     <br />
P \Rightarrow Q \Leftrightarrow \neg P \vee Q<br />
     <br />
P \Rightarrow Q \Leftrightarrow \neg (P \wedge \neg Q)<br />
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