# Conjunction Disjunction confuse.

• Feb 1st 2010, 09:46 AM
iMoons
Conjunction Disjunction confuse.
Given the pair of statements

p : If 3 >2, then 3 x 0 > 2 x 0

q: If 4=5, then 5=9
Write their conjunction and disjunction, indicating the truth value of each compound statement formed.

The problem above confuse me. I know this type of problem though.

p: One is an even integer. q: Nine is a positive integer.
A. (a) One is an even integer and nine is a positive integer.
(b) One is an even integer or nine is a positive integer. (T)
• Feb 1st 2010, 10:01 AM
Plato
Do the new problem exactly as you have done in the sample you gave.
Just realize that q is false and p is true.
• Feb 1st 2010, 10:44 AM
iMoons
Is this how the answer should be? It confuse me because these number don't look right (Headbang).
a) Conjunction
If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0
• Feb 1st 2010, 11:02 AM
Plato
Quote:

Originally Posted by iMoons
Is this how the answer should be? It confuse me because these number don't look right (Headbang).
a) Conjunction
If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0

I cannnot say if they are correct or not.
You understand that I did not give the assignment so I don't know what is expected.
However, the first is a conjunction of the two. It is false.
The second is a disjunction. It is true.
• Feb 1st 2010, 11:07 AM
iMoons
Ok. Thank you. It clear to me now. :)
• Feb 1st 2010, 11:19 AM
novice
Quote:

Originally Posted by iMoons
Is this how the answer should be? It confuse me because these number don't look right (Headbang).
a) Conjunction If 4=5, then 5=9 , and If 3 >2, then 3 x 0 > 2 x 0
a) Disjuntion If 4=5, then 5=9 , or If 3 >2, then 3 x 0 > 2 x 0

Try these:
\$\displaystyle
P \Rightarrow Q \Leftrightarrow \neg P \vee Q
\$
\$\displaystyle
P \Rightarrow Q \Leftrightarrow \neg (P \wedge \neg Q)
\$