Prove by mathematical induction 1 + 3 + 3^2 + ... + 3^(n-1) = [3^(n-1)] / 2 . i really need helpp, i really don't get it after the second step.
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Originally Posted by phillychum Prove by mathematical induction 1 + 3 + 3^2 + ... + 3^(n-1) = [3^(n-1)] / 2 . i really need helpp, i really don't get it after the second step. Hi phillychum, it should read If this is true, then should We can prove if this is the case by adding to both sides of the original equality. This means that if then Hence the inductive step is proven. Now it only needs to be proven for term number 1.
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