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**flabbergastedman** I apologize if this has been posted before. I have done many searches, but most ended up proving the Binomial Theorem. Anyhow, here goes:

Prove $\displaystyle 1^3 + 2^3 + 3^3 + ... + n^3 = (1 + 2 + 3 + ... + n)^2$

I'm basically looking for a shove in the right direction, as my induction step:

$\displaystyle P(k + 1) : 1^3 + 2^3 + ... + k^3 + (k + 1)^3 = ??? $

I'm unsure here since the RHS can be: $\displaystyle (1 + 2 + ... + k + [k+1])^2 $ or $\displaystyle (2 + 3 + ... + 2k)^2 $

which is where my confusion begins. Thoughts?