My question Prove that $\displaystyle 3^n > n!$ whenever n is a positive integer greater than 6
Can you help me please ı can't solve this proof
Note that $\displaystyle \frac{3^n}{n!}=\frac{3}{n}\cdots\frac{3}{n}$ and show that this is less than one. Prove that there is an injection from the set of all permutations of $\displaystyle \left\{1,\cdots,n\right\}$ to the set of all true ordering relations on $\displaystyle \left\{1,\cdots,n\right\}$. etc.