4 men and their wives , 4 bachelors and 4 spinsters are travelling in two 8-seater compartments of a train , one of which is a smoking compartment while the other is not . In how many ways can the party be split up if no wife is separated from her husband ?
January 11th 2010, 04:55 AM
I'm not sure about the method, but here goes:
Pair up each husband and wife as a "couple". So we have 4 couples, 4 bachelors and 4 spinsters.
Effectively we have 12 "seats"
Now, let's take the following cases.
1. All couples in one compartment .
No. of ways this can be achieved is 2