Hello ps1313No. Try a few values of , and work out :So instead of taking pairs of values of , even and odd, you'll have to take groups of 3, depending on the remainder 0, 1 or 2, that leaves when divided by 3.
... and so on.
I haven't worked it out, but I suspect that you'll need to link and now, rather than and . Try it and see.
Grandad