2x 1 (mod 7) 5x 2 (mod 11) I know how to do the CRT, but the fact that this prob. has coefficients in front of the x is confusing me. How do I go about solving this?
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We can rewrite them as: From these we can write: ...[1] Appyling modulo 7 to and we get: Sub into the right side of [1]: The solutions to the system are: Which can be written as Let and they will satisfy the system of linear congruences.
I see...thanks for your help!
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