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- February 14th 2007, 09:14 PMchillerbros17Checkerboard: Use proof by contradiction
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- February 15th 2007, 12:01 AMCaptainBlack
Suppose it can be made from the given tiles, then there will be 15 of them.

This is because there are 60 small squares on the board to be covered, 30

light and 30 dark.

So there must be an even number of one type of tiles and an odd number of

the other.

Now the tile type that is used an even number of times is covering an even

number of light squares and an even number of dark squares.

Also the tile type that is used an odd number of times is covering an odd

number of light squares and an odd number of dark squares (as the two

tile types both have an odd number of light and dark squares in them).

So the tiling covers an odd number of light squares and an odd number of

dark squares, which as the board actualy has an even number of both

is a contradiction. Hence no such tiling exists.

RonL - February 15th 2007, 09:18 AMSoroban
Hello, chillerbros17!

There are 30 black squares and 30 white squares to be covered.

Each type-A tile covers 1 black and 3 white squares.

Each type-B tile covers 3 black and 1 white squares.

A pair (AB) covers 4 black and 4 white squares.

Using seven pairs of tiles, we can cover 28 black and 28 white squares.

But there will be 2 black and 2 white squares remaining to be covered.

It is impossible to cover them with either a type-A or a type-B tiles.