1. ## Sets Problem

Hi Friends,

In a village of 100 households, 75 have atleast one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If X and Y are respectively the greatest and lowest possible number of house holds that have all the three of these devices, X – Y is
A.65 B.55 C.45 D.35 E.25
Any solutions for the above problem ..?
Regards,
AVR.

2. Originally Posted by AVR
Hi Friends,

In a village of 100 households, 75 have atleast one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If X and Y are respectively the greatest and lowest possible number of house holds that have all the three of these devices, X – Y is
A.65 B.55 C.45 D.35 E.25
Any solutions for the above problem ..?
Regards,
AVR.
Where are you stuck? Have you attempted it?

3. Hi Aman,

I tried it before posting it on the forum, and i got the greatest possible of house holds having all the three value as 55 . I had approached in different ways for finding the "lowest possible value of households having all the three " but unable to get correct value.

Any solutions or ideas regarding the problem will be appreciated...

Regards,
AVR.

4. Originally Posted by AVR
Hi Aman,

I tried it before posting it on the forum, and i got the greatest possible of house holds having all the three value as 55 . I had approached in different ways for finding the "lowest possible value of households having all the three " but unable to get correct value.

Any solutions or ideas regarding the problem will be appreciated...

Regards,
AVR.
Hint: Draw the venn diagram. Put the values. Put the possible max/min for each of the sections in the venn diagram. You should get the answer. I haven't tried it myself. But this should be the first starting point. Thanks