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Math Help - Sets Problem

  1. #1
    AVR
    AVR is offline
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    Smile Sets Problem

    Hi Friends,

    In a village of 100 households, 75 have atleast one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If X and Y are respectively the greatest and lowest possible number of house holds that have all the three of these devices, X Y is
    A.65 B.55 C.45 D.35 E.25
    Any solutions for the above problem ..?
    Regards,
    AVR.
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  2. #2
    Super Member
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    Quote Originally Posted by AVR View Post
    Hi Friends,

    In a village of 100 households, 75 have atleast one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If X and Y are respectively the greatest and lowest possible number of house holds that have all the three of these devices, X Y is
    A.65 B.55 C.45 D.35 E.25
    Any solutions for the above problem ..?
    Regards,
    AVR.
    Where are you stuck? Have you attempted it?
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  3. #3
    AVR
    AVR is offline
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    Hi Aman,

    I tried it before posting it on the forum, and i got the greatest possible of house holds having all the three value as 55 . I had approached in different ways for finding the "lowest possible value of households having all the three " but unable to get correct value.

    Any solutions or ideas regarding the problem will be appreciated...

    Regards,
    AVR.
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  4. #4
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    Quote Originally Posted by AVR View Post
    Hi Aman,

    I tried it before posting it on the forum, and i got the greatest possible of house holds having all the three value as 55 . I had approached in different ways for finding the "lowest possible value of households having all the three " but unable to get correct value.

    Any solutions or ideas regarding the problem will be appreciated...

    Regards,
    AVR.
    Hint: Draw the venn diagram. Put the values. Put the possible max/min for each of the sections in the venn diagram. You should get the answer. I haven't tried it myself. But this should be the first starting point. Thanks
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