In a village of 100 households, 75 have atleast one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If X and Y are respectively the greatest and lowest possible number of house holds that have all the three of these devices, X – Y is
A.65 B.55 C.45 D.35 E.25
Any solutions for the above problem ..?
I tried it before posting it on the forum, and i got the greatest possible of house holds having all the three value as 55 . I had approached in different ways for finding the "lowest possible value of households having all the three " but unable to get correct value.
Any solutions or ideas regarding the problem will be appreciated...