How many ways can you distribute 42 objects among 8 people if the first 4 must get exactly 25 between them? Is it: $\displaystyle \frac{8!}{4!4!}4^{25}4^{17}$ or just: $\displaystyle 4^{25}4^{17}$ or neither?
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Originally Posted by billym How many ways can you distribute 42 objects among 8 people if the first 4 must get exactly 25 between them? I think that this is very odd question. But the answer I would give is: $\displaystyle \binom{42}{25}4^{25}4^{17}$.
Forgot to mention that the objects are identical.
Originally Posted by billym Forgot to mention that the objects are identical. Well that was a real oversight. $\displaystyle \binom{25+4-1}{25}\binom{17+4-1}{17}$
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