G={+/- 1, +/- i, +/- j, +/- k} H={1, -1} How do I construct the cayley table for G/H?
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Originally Posted by jujab G={+/- 1, +/- i, +/- j, +/- k} H={1, -1} How do I construct the cayley table for G/H? The basic laws are: $\displaystyle i^2=j^2=k^2=-1\,,\,\,ij=k\,,\,\,jk=i\,,\,\,ki=j$ . Try now to have some fun proving that if you reverse the order of the above products you get minus the result, i.e. $\displaystyle ji=-k\,\,and\,\,etc.$ Tonio
Ok, thanks!
Last edited by jujab; Nov 5th 2009 at 09:49 AM.
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