Yes, your approach looks fine.
A history exam paper contained 8 questions. 4 from Part A and 4 from Part B. Candidates are required to attempt 5 questions. In how many ways can this be done if at least 2 questions from Part A and at least 2 questions from Part B must be chosen.
So, what I did was,
2(4C3*4C2)= 48
So, i wanna ask, is my approach correct ??
Please Help !