Prove that for each f:X -> exists Z, h:X ->Z injective and y: Z ->Y surjective, so that f= gh

Just can't figure it out. Hope the thing is understandable, not really used to translating maths =P.

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- October 20th 2009, 10:27 AMLetharProving problem in set theory
Prove that for each f:X -> exists Z, h:X ->Z injective and y: Z ->Y surjective, so that f= gh

Just can't figure it out. Hope the thing is understandable, not really used to translating maths =P.