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Math Help - one more attempt

  1. #1
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    one more attempt

    I assume that P(n) is true

    p(n): j - i < 2^n => A(i,j) \leq n

    for all Z i , j , n with
    1 \leq i \leq j \leq N

    and n \leq 0

    basic step: P(0)

    j - i < 1 => A(i,j) \leq 0

    now I need to prove P(n+1)
    P(n+1) : j - i < 2^(n+1) => A(i,j) \leq n+1

    meaning I have to show that A(i,j) \leq n+1

    how?
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  2. #2
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    Quote Originally Posted by Madspeter View Post
    I assume that P(n) is true

    p(n): j - i < 2^n => A(i,j) \leq n

    for all Z i , j , n with
    1 \leq i \leq j \leq N

    and n \leq 0

    basic step: P(0)

    j - i < 1 => A(i,j) \leq 0

    now I need to prove P(n+1)
    P(n+1) : j - i < 2^(n+1) => A(i,j) \leq n+1

    meaning I have to show that A(i,j) \leq n+1

    how?

    Do you realize that we have no idea what is P, what is A and what are you talking about at all?

    Tonio
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  3. #3
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