Thread: one more attempt

I assume that P(n) is true

p(n): j - i < 2^n => A(i,j) n

for all Z i , j , n with
1 i j N

and n 0

basic step: P(0)

j - i < 1 => A(i,j) 0

now I need to prove P(n+1)
P(n+1) : j - i < 2^(n+1) => A(i,j) n+1

meaning I have to show that A(i,j) n+1

how?

Originally Posted by Madspeter

I assume that P(n) is true

p(n): j - i < 2^n => A(i,j) n

for all Z i , j , n with
1 i j N

and n 0

basic step: P(0)

j - i < 1 => A(i,j) 0

now I need to prove P(n+1)
P(n+1) : j - i < 2^(n+1) => A(i,j) n+1

meaning I have to show that A(i,j) n+1

how?

Do you realize that we have no idea what is P, what is A and what are you talking about at all?

Tonio

http://www.mathhelpforum.com/math-he...tion-more.html


forgot to link this one.