I don't even know how to begin this problem. Induction maybe?
Prove: If a in R,
a does not = 0,
a > -1
Then: for all k in N, [ (1+a)^k+1 ] > [ 1 + (k+1)a ].
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Look at this disscusion
I see the equations are slightly different. But I'm still having a litte trouble. Do I prove it true for a,k=1
then in the inductive step prove it true for a=a+1 and k=k+1?
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