A commision of 5 person is to be chosen from 6 men and 4 women. In how many ways can this be done,

1 if there must be 3 men and 2 women

2 more men than women

3 there must be 3 men and 2 women and one particular woman refuses to be on the comittee with one particular man ?

I did this

6 x 5 x 4 x 4 x 3 = 1440, doesn't seem to be right answer, 120 is the answer, could anyone explain me this and when to use combination and permutation, Thank you very much