# [SOLVED] one-to-one function or not?

• Oct 4th 2009, 07:26 PM
smith.5954
[SOLVED] one-to-one function or not?
thanks
• Oct 5th 2009, 12:02 AM
Gamma
i think the biggest problem is that function is not well defined.

$f(1/2)=2\cdot 1 + 2=4$ but
$f(2/4)=2 \cdot 2 + 4= 8$

Even if it were well defined, its not injective
$f(3/4)=f(1/8)$ but clearly $3/4 \not = 1/8$