Thread: Is this argument valid?

I have to find out whether this argument is valid or invalid:

p -> q
(q v ([not]r)) -> (p [and] s)
s->(r v q)

Hope that makes sense, and also I appreciate any help that can be offered. Thanks.

Originally Posted by GreenDay14

I have to find out whether this argument is valid or invalid:

p -> q
(q v ([not]r)) -> (p [and] s)
s->(r v q)

Hope that makes sense, and also I appreciate any help that can be offered. Thanks.

If im not mistaken it's valid.

You can check for yourself, if you find values for s,r,p and q that makes the result false but the statements true, then the argument is invalid

Hello GreenDay14

Originally Posted by GreenDay14

I have to find out whether this argument is valid or invalid:

p -> q
(q v ([not]r)) -> (p [and] s)
s->(r v q)

Hope that makes sense, and also I appreciate any help that can be offered. Thanks.

I've drawn up a truth table for the proposition



- see attachment.

The columns are evaluated in order (1) through (8) - (8) being the final output. Since this show TRUE in every row, then, yes the argument is valid.

Grandad