I have to find out whether this argument is valid or invalid:

p -> q

(q v ([not]r)) -> (p [and] s)s->(r v q)

Hope that makes sense, and also I appreciate any help that can be offered. Thanks.

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- October 1st 2009, 08:57 PMGreenDay14Is this argument valid?
I have to find out whether this argument is valid or invalid:

p -> q

__(q v ([not]r)) -> (p [and] s)__s->(r v q)

Hope that makes sense, and also I appreciate any help that can be offered. Thanks. - October 4th 2009, 08:41 AMJones
- October 4th 2009, 09:22 AMGrandad