I've come this far: an = 4an-1 + 5an-2 a1 = 2 a2 = 6 roots x1 = 5 x2 = -1 I insert roots in : an = U*s1^n + V*s2^n which gives : an = 4*5^n + 5*(-1)^n what now? an could e.g. be a1?
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Hello Madspeter Originally Posted by Madspeter I've come this far: an = 4an-1 + 5an-2 a1 = 2 a2 = 6 roots x1 = 5 x2 = -1 I insert roots in : an = U*s1^n + V*s2^n Correct, except that you mean x1 and x2 - see below which gives : an = 4*5^n + 5*(-1)^n No what now? an could e.g. be a1? Thanks for showing us your working so far. What you mean is: Then plug in the values : Can you complete it now? Grandad
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