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Thread: sum of squares

  1. September 28th 2009, 08:18 AM #1
    Sampras
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    sum of squares

    Suppose we want to find a closed formula for the sum of the N squares. Start with the formula \sum_{n=0}^{N} x^n = \frac{x^{N+1}-1}{x-1} . Then do we do the following:

    \sum_{n=0}^{N} (xD)^n = \frac{(xD)^{N+1}-1}{(xD)-1}

    e.g. apply the (xD)^2 operator?
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  2. September 28th 2009, 10:12 AM #2
    Moo
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    What do you call an (xD)² operator ?

    And yes the second formula is correct too...
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