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Math Help - sequences...

  1. #1
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    sequences...

    a_{n+1}=a_n+\frac{1}{2^{n+1}}
    n\geq 0
    a_0=1

    I need to write a_{n+1} in terms of \frac{1}{2}a_n

    I've written out the first few terms... but I'm just not seeing it... apparently this is a geometric sequence if that helps...

    Thanks.

    Also, while I'm here, what's the TeX code to put a space? Cheers
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  2. #2
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    Quote Originally Posted by Aileys. View Post
    a_{n+1}=a_n+\frac{1}{2^{n+1}}
    n\geq 0
    a_0=1

    I need to write a_{n+1} in terms of \frac{1}{2}a_n

    I've written out the first few terms... but I'm just not seeing it... apparently this is a geometric sequence if that helps...

    Thanks.

    Also, while I'm here, what's the TeX code to put a space? Cheers
    Question - Is it

    a_{n+1}=a_n+\frac{1}{2^{n+1}},\;\;n\geq 0,\;\;a_0=1

    or

    a_{n+1}=a_n+\frac{1}{2^{n}},\;\;n\geq 0,\;\;a_0=1

    As for spaces, the easiest is using \, (small) or \; (regular)
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  3. #3
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    Quote Originally Posted by Danny View Post
    Question - Is it

    a_{n+1}=a_n+\frac{1}{2^{n+1}},\;\;n\geq 0,\;\;a_0=1

    or

    a_{n+1}=a_n+\frac{1}{2^{n}},\;\;n\geq 0,\;\;a_0=1

    As for spaces, the easiest is using \, (small) or \; (regular)
    It says a_{n+1}=a_n+\frac{1}{2^{n+1}},\;\;n\geq 0,\;\;a_0=1... but maybe it's a typo... can you answer the question if it's
    a_{n+1}=a_n+\frac{1}{2^{n}},\;\;n\geq 0,\;\;a_0=1? I still can't :S


    Thanks for your help
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